# Distance between Two Points Calculator

If you want to calculate distance between two points of cartesian coordinates, you can use the below 2D distance calculators. You have to enter the two points which is denoted by (x1, y1) and (x2, y2).  Hit the calculate button and you will see result. In the last part of this page, the tricks of determining the distance between two points is discussed through developing the concept of the Cartesian coordinate system.

## Distance between Two Points Calculator

Fill the coordinate & click on calculate button to calculate

First Co-Ordinate

X1
Y1

Second Co-Ordinate

X2
Y2
Distance between Two Points Calculator
First Co-Ordinate( X1, Y1) (0,0)
Second Co-Ordinate( X2, Y2)(0,0)
Distance between Two Points √(( X1- X2) 2+( Y1- Y2) 2) O Units

## What is Rectangular Cartesian Coordinate?

For determining the proper position of any definite point, it is necessary to know the distance of the definite point from the straight-line bisectors constructed on the plane. It is said as a reason that only a point can lie at any definite distance from two straight line bisectors. If two such straight lines XOX and YOY are drawn that intersect each other at a right angle on any plane, XOX is called the x-axis, YOY' is called the y-axis and the intersecting point O is called the origin.

Now, let P  be any point on the plane of the two axes. from point P, on XOX’ i.e., the x-axis and on YOY' i.e., the y-axis, the perpendiculars are respectively PM and PN.

Then the distance of point P from the y-axis = NP = 0M = x is called the abscissa of P or x-coordinate.  Again, the distance of P from the x-axis == MP = ON = y is called the ordinate of p or y-coordinate. The abscissa and the Ordinate are jointly called the Coordinate.

So, in the figure, the coordinate of P means the perpendicular distance of P from the y-axis and the x-axis and by denoting them as x and y, the coordinate of P is expressed by the symbol P(x,y)

The coordinate index (x, y) means an ordered pair whose first element indicates the abscissa and the second element indicates the ordinate. so, if y, by (x, y) and (y, T), two different points are meant.

Therefore, the coordinate of any point depending on two axes intersecting each other at the right angle is called the Rectangular Cartesian Coordinates. If the point is placed at the right side of the y-axis, the abscissa will be positive and if it is placed at the left side, the abscissa will be negative. Again, if the point is placed above the X-axis, the ordinate will be positive and if it is placed below, the ordinate will be negative. On the x-axis, the ordinate will be zero and on y-axis, the abscissa will be zero. So, the positive abscissa and the ordinate of any point will be along OX and OY respectively or parallel to them. Similarly, the negative abscissa or the ordinate will be along OX' and OY' respectively or parallel to them.

By the two axes Of the Cartesian coordinates, the plane is divided into XOY, YOX' X'OY', Y'OX these four parts. Each of them is called a quadrant. The quadrant XOY is taken as the first and by turns the second, the third and the fourth quadrant remain in anti-clockwise order. According to the sign of the point of the coordinate, the point lies on the different quadrants.

## How to Calculate Distance between two points?

Let, P (x1, y1) and Q (x1, y1) be the two different points on a plane. from points P and Q, perpendiculars PM and QN are drawn on x-axis. Again, from point P, draw perpendicular PR on QN. Now the abscissa of point P is = 0M = x1 and the ordinate of point P is = MP = y1.

The abscissa of point Q is = ON = x2 and the ordinate NQ is = y2.

From the figure we get,

PR = MN = ON-OM = x2 - x1

QR = NQ -NR = NQ-MP = y2-y1

As per the construction, PQR is a right-angled triangle and PQ is the hypotenuse of the triangle. So, as per the theorem of Pythagoras,

PQ² = PR² + QR²

or, PQ = √(PR² + QR² )

Therefore the distance between two Cartesian points is: √(PR² + QR² )

Example: Find the distance between 1,1 and (2,2)

Solution:

Let P (1,1) and Q (2,2) be the given two points/ The distance between two points is

PQ = √((2-1)² + (2-1)² )

PQ = √(1²+ 1² )

PQ = √1+1

PQ = 1.4142